For your current way diagram the output would be the voltage divided value at the point labeled out.

For your other way diagram, it depends. If you hooked a meter to the out without any other circuitry attached to the out you'd get whatever the +in voltage is applied. If there is other circuitry attached and there is current flow in the circuit you'd get some voltage dropped across the top resistor. It might be the whole +in but probably less than full voltage supplied. Even if the output is grounded you wouldn't get a voltage divided value across either resistor you'd get power divided across two resistors. Something altogether different.