How to detect low battery in battery powered F683 circuit


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  1. #1
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    Aug 2008
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    Default Re: How to detect low battery in battery powered F683 circuit

    Hi;
    The 12f1840 as Internal voltage reference ( Fixed Voltage Reference (FVR) with 1.024V, 2.048V and 4.096V output levels )
    Thanks and Regards;
    Gadelhas

  2. #2
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    Sep 2008
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    Maine, USA
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    Default Re: How to detect low battery in battery powered F683 circuit

    Thanks guys! Now I completely understand what I need to do and this solution will work extremely well for me. I have ordered some sample chips and will dig into this later in the week. I appreciate your help and patience.
    "Do or do not, there is no try" Yoda

  3. #3


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    Default Re: How to detect low battery in battery powered F683 circuit

    Hi Tekart,
    Do you have PBP3 ? I believe you will need it to use the 12F1822 or any xxF1xxx part.

  4. #4
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    Default Re: How to detect low battery in battery powered F683 circuit

    Quote Originally Posted by Dick Ivers View Post
    Hi Tekart,
    Do you have PBP3 ? I believe you will need it to use the 12F1822 or any xxF1xxx part.
    Of course! Been using PIC Basic for over 14 years! Early adopter that came over from Basic Stamps. - thanks for checking though
    "Do or do not, there is no try" Yoda

  5. #5


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    Default Re: How to detect low battery in battery powered F683 circuit

    Maybe this will help. A while back we needed a low battery warning for a circuit that was already in production so it had to be done in reverse. The PIC was powered by a 6V battery with a diode to drop it to 5.4V. A jumper from an ADC pin was attached to a 3.3V regulator already on another section of the circuit board. Now as the battery voltage drops, the ADC result will rise, since the 255 reference will always be the battery voltage. The lower the battery voltage the higher the 3.3V ADC reading becomes.

  6. #6
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    Default Re: How to detect low battery in battery powered F683 circuit

    That is what I was suggested, just to to use diode instead of regulator...

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