Fluctuating digital inputs

[pedja089]

That spikes can easily kill pic. Not single spike, but repeated...
This is simplest circuit that will protect pic, and give you good immunity to spikes.

Also this circuit add little delay...
And use twisted pair for wiring remote switch, it should improve situation.

[The Master]

A very small delay isn't really a problem. The chip is currently sampling each input at over 300,000 times per second but it wouldn't really matter if it were only 100 times per second. I can't imagine the cap would add a delay much longer than that.

I might be able to solder the capacitors under the PCB and the 2K-R12 resistor would have to be on the wire but since that's in series it's position shouldn't matter.

I don't think any of the spikes go high enough to cause a problem with the PIC. I've never seen one get up to 3.3V. The negative ones may be a problem though.

Thanks for your help. I'll try the extra cap/resistor as it looks to be a simple mod and see what the Oscope looks like.

[pedja089]

R12 should be on PCB side of cable. Because long wire have a capacitance to ground.
Spikes are clamped to -0,7V and +4V by pic internal diodes.
Negative voltage on input pin can latch new pic.

[HenrikOlsson]

Hi,
Thanks for doing the schematic pedja089 - that's exactly what I'm talking about. The 15k, 2k will give a low level of 0.39V. I looked at a 18F2420 datasheet and it states max voltage for a logic low on a schmitt trigger input to be 0.2Vdd or 0.66V with a 3.3V supply so you're below that by some margin - but not much. Definitely worth a try. Double check against correct datasheet!

but since that's in series it's position shouldn't matter.

Yes, I'd say it matters. You want the cap close to the PIC and the resistor close to the cap - not at the switch.
If you're trying to filter noise generated from the switch itself bouncing etc then it wouldn't matter but in this case you're trying to filter out noise being coupled into the wires. If you put the resistor far away from the capacitor (which you want close the actual input pin) the noise can be coupled into the part of the wire between the resistor and capacitor basically negating the resistor.

A simple software based low pass filter will most likely work as well but a little bit of hardware filtering is "the right way" and will provide some protection for the input.

/Henrik.

[The Master]

I will have to put the resistor inside the plug which is on the circuit end of the wire then. That's as close as I can get it without cutting through traces on the PCB. It still puts the resistor within 3 inches of the PIC though.

The PIC I'm using is a PIC24FJ64GA002. I'm pretty sure the datasheet said VSS-0.2V is low and 0.8-VDD is high.

[pedja089]

That is just print scr, from my schematic.
My Vdd is 2.8V, so lower threshold is 0.56V. With 2K and 15K combination low level is 0.32V.
That is almost half of threshold, it works fine for me.

[Dave]

Bandaids,Bandaids,Bandaids, Just put an optoisolator and a couple of resistors on a small piece of Vectorboard and be done with it. If you are going to use the circuit in post #382 you might as well do it right with anh opto.

[pedja089]

If you referring to my post #14...
My circuit use only 10uA with all inputs shorted to GND.
Vdd for inputs is controlled by PIC. So just give me opto that uses less than 1uA and I'll be happy to use it.
By the way device passed ESD and RF immunity test without false triggering or any damage

[pedja089]

Double post. Bad internet connection...