how to access and set bits in a byte array?

[richard]

pretty much
bArrRGBData.0[8] is bit 0 of bArrRGBData[0] bit 0 + 8 bits , ie bArrRGBData[1] bit 0
you can place it in any var but its value can only be 0 or 1
can also be used as a logical value ie.

if bArrRGBData.0[8] then dosomething
else
doanotherthing
endif

[richard]

just a warning pbp does not ckeck the boundary conditions of this type of indexing
if you were to
go
bArrRGBData.0[41] =1
there is no error message and anything in the next ram/register position from bArrRGBData[4] would be wrecked

[dsicon]

pretty much
bArrRGBData.0[8] is bit 0 of bArrRGBData[0] bit 0 + 8 bits , ie bArrRGBData[1] bit 0
you can place it in any var but its value can only be 0 or 1
can also be used as a logical value ie.

if bArrRGBData.0[8] then dosomething
else
doanotherthing
endif

thanks for you help, am removing some rust here due to inactivity
what bothered me for a bit (pun intended) was whether this would by syntax return a single bit, i realize now that the .0 portion says that and explaining that bArrRGBData.0[8] is equivalent to bArrRGBData[1] bit 0 is just what i needed
i also understand the risk about overrunning the allocation

[dsicon]

how about these cases
MyWordArray VAR WORD[8]

what does the following do exactly ?
MyWordArray = 0
does it set the first byte of the Array to 0 and leaves the rest as was ?

what if there is a word variable used instead
AWord VAR WORD
MyWordArray VAR WORD[8]
AWord = 0
MyWordArray = AWord
now are the first 2 bytes set to 0 ?
just curious ....