Forgotten that PBP has not the power. Well you can use the shift left. Every shift you multiply by two so B1 = B0 << val where B0 = 1. Still need the filter to turn the one into zero, when val = 0.
Cheers
Al.
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Re: better way to do this using math
Forgotten that PBP has not the power. Well you can use the shift left. Every shift you multiply by two so B1 = B0 << val where B0 = 1. Still need the filter to turn the one into zero, when val = 0.
Cheers
Al.
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