better way to do this using math

[longpole001]

the manual shows " ^ " to be a bitwise exclusive OR ?

[aratti]

Forgotten that PBP has not the power. Well you can use the shift left. Every shift you multiply by two so B1 = B0 << val where B0 = 1. Still need the filter to turn the one into zero, when val = 0.

Cheers

Al.