Hello all,
The opto route looks very interesting, I have to say. I'll have to do some further studying on that. As far as my second post/reply, I apologize because I believe I misspoke in calling the op amp a "differential", instead of an "inverting" like it is. The simulation shows the "Clamp" to be an active participant but it is, in fact, ground. As far as the voltages on the "Torch" voltage divider, they will range from -100 to -275 vdc. The sim shows it as AC but, I think I mislead you fine folks. I was simulating it with an AC signal, although I neglected to mention it has a -150 DC offset. Sorry for not being more clear. Now that I hope I have given you guys the info you needed to begin with (my bad)...since the inverting input will never see positive voltage, therefore the op amp is not expected to invert it into a negative voltage output, do the same split supply rules still apply? Just for the heck of it, I removed the DC offset from the AC signal in ISIS (swings above and below ground) and the o-scope showed what I predicted...when the AC swung positive, the DC output was at ground...when the AC swung negative, the DC output followed the sine wave (+). Maybe I'll whip it up on the breadboard, just for the heck of it...
Any more thoughts or input is always appreciated!
Thanks guys,
Chris