touble with a time calculation

[longpole001]

the reason for the enable is that until the time = > the setting , the output is not displayed , also the enable flag is used for other routines , hardware options and other timers., also if the values of the Set time all are 0 then that disables the flag for this timer for display on the Glcd's and other outputs

there are several timer clock options that need to show - time in secs only , mins+ sec only , hours,min, sec only ,currently these options turn off / on flags inside the main up/ down timer counter code to enable hours, mins ,sec changes

by changing the values to 59 from 60 for say the secs this results in the following

if set_hour= 0 set_min = 0, Set_sec = 10

if main elapsed time now shows = 0 hour, 1 min , 0 sec

If OT_sec = 60 - Set_sec + Seconds(main elapsed ) then

OT display = 50 (60 - 10 + 0)

if OT_sec = 59 - Set_sec + Seconds(main elapsed ) then

OT display = 49 (59 - 10 + 0)

if the event time was set for 10 sec and the main time is now 1 min then the overtime should read 50secs , not 49 sec

I think i have this correct , but i am still testing
cheers

Sheldon

[richard]

if you have a clock running
try this
h m s var bytes (current time )
x y z var byte (old time )
a b c var byte ( time difference)
carry var bit

time_difference: (assumes current time > old time)
carry=0
c=s-z
if c>127 then
c=c+60
carry=1
endif
b=m-(y+carry)
if b>127 then
b=b+60
carry=1
else
carry=0
endif
a=h-(x+carry)
if a>127 then
a=a+24
carry=1 ;extra day needed to be added
else
carry=0
endif
return

[longpole001]

time problem sorted , thanks steve for your help on that , cheers m8

next part flash / data transfer from program mem to flash - problems never seems to stand still for long