How do I discern Maidenhead Locator from GPS lat long info.

[richard]

anyway as i said in the begging im an amature in programming and is not my main job. I do it on my spare time and i try to make as simple as possible

you may think your way is as simple as possible but its not , its the hardest way by far.
my way breaks the task up into simple logical blocks , each task can then be solved independently ,and in isolation from the other tasks
the entire project can be built one task at a time

task1
read in nmea scentence
task2
verify crc
task3
identify scentence type
task 4
parse a GPRMC scentence

task4a
process a time field

task4b
process a LAT field
task4c
process a LON field

.....etc

simple small steps

[astanapane]

you may think your way is as simple as possible but its not , its the hardest way by far.
my way breaks the task up into simple logical blocks , each task can then be solved independently ,and in isolation from the other tasks
the entire project can be built one task at a time

task1
read in nmea scentence
task2
verify crc
task3
identify scentence type
task 4
parse a GPRMC scentence

task4a
process a time field

task4b
process a LAT field
task4c
process a LON field

.....etc

simple small steps

Ok if i cannot make it the way i have started, i will follow your advice, as given above.

[astanapane]

Hi Richard,

i think it is working. I need to test it one or two days....

I'll keep you updated because i need also to understand the "true" statement.

[astanapane]

Sorry forgot to upload the code.

The following is the one i have changed in order the date to change when the time is > 23

day_added = 0
hh = hh + 3
if  hh > 23 then
day_added = 1
endif
hh = hh//24
if day_added = 1 then
day = day + 1
if day > num_date then ; i havent done anything to this up to now. I need to figure out how to tell the programm about the num_date (No of the day today in this month)
day = 1
if month > 12 then
month = 1
year = year +1
    endif
      endif
        endif

regarding this

if day > num_date then ; i havent done anything to this up to now. I need to figure out how to tell the programm about the num_date (No of the day today in this month)

i think that i need to create a table with 12 months and specify which has 30, 31, or which year then has Feb 28 or 29

[richard]

the only thing I might add is that the conversion from utc to local time only needs to be done if and when the hour changes , its not needed in every loop.
a flag can be set when the utc hour now is != current utc hour , then the flag can be cleared when the conversion is done

[astanapane]

the only thing I might add is that the conversion from utc to local time only needs to be done if and when the hour changes , its not needed in every loop.
a flag can be set when the utc hour now is != current utc hour , then the flag can be cleared when the conversion is done

Hi Richard, once again thanks a lot for your kind help and time.

I work on this very slow, because i need to understand the code, and then i need to test the code every time i change something.

Now i need to fix the months. Please give me some time. I will upload the code and then we can discuss what might need to be done.

As i have it in mind, i need to create a label. Under the label i need to speciafy which month has 30 days and which has 31 at the begging. For the month February i need to specify which YEAR is 28 days and which is 29.

Then i will connect the code:

ay_added = 0
hh = hh + 3
if  hh > 23 then
day_added = 1
endif
hh = hh//24
if day_added = 1 then
day = day + 1
if day > num_date then ; i havent done anything to this up to now. I need to figure out how to tell the programm about the num_date (No of the day today in this month)
day = 1
if month > 12 then
month = 1
year = year +1
    endif
      endif
        endif

to the Label which has all the info for each month.

Is that right?

[richard]

getting the number of day in month can be achieved in a few ways

simple is lookup
but resource hungryLOOKUP Index,[Constant{,Constant...}],Var

lookup month,[0,31,28,31,30,,,,,,,,,,,,,],numberofdays

an array
more efficient but uses more sram
arraywrite ndays,[0,31,28,31,30,,,,,,,,,,,,,]
numberofdays=ndays[month]


leap years
are

if ((year//4 = 0) and (year//400 !=0))
if month=2 then numberofdays=numberofdays+1
endif