How do I discern Maidenhead Locator from GPS lat long info.

[richard]

if your time offset from utc is 3.00 hours then the minutes and seconds are irrelevant.
after adding your offset then you need to check if the new hours is >23
if so then add a day to the date then test if that is greater
than the number of days for that month [ don't forget leap years / leap centuries],
then increment the month if there are too many days
you may even need to increment the year , not forgetting to set the new day/month to the appropriate value after all
the incrementing and the new hour to modulo 24

better still get a raspberry pi use python datetime
now=datetime.datetime.utcnow()+datetime.timedelta( hours=3)
and it does everything in one line

[astanapane]

if your time offset from utc is 3.00 hours then the minutes and seconds are irrelevant.
after adding your offset then you need to check if the new hours is >23
if so then add a day to the date then test if that is greater
than the number of days for that month [ don't forget leap years / leap centuries],
then increment the month if there are too many days
you may even need to increment the year , not forgetting to set the new day/month to the appropriate value after all
the incrementing and the new hour to modulo 24

better still get a raspberry pi use python datetime
now=datetime.datetime.utcnow()+datetime.timedelta( hours=3)
and it does everything in one line

ok im trying now to understand your logic which is clear but for me a bit difficult to transfer it to code.

Lets start.

if your time offset from utc is 3.00 hours then the minutes and seconds are irrelevant.

hh = hh +3
hh = hh//24

after adding your offset then you need to check if the new hours is >23

if hh > 23

At the next sentense i have a difficulty to understand how to write the code.
if so then add a day to the date then test if that is greater

DAY = DAY +1

My understanding is, that when the

hh > 23

then with the command

DAY = DAY + 1

we see the change only if numerically the Hour goes to 24.

But we said that hh will not exceed the number 23, after that and correctly will go to 00.

So i need to find the way to tell the code that every time hh goes to 00 to change the date. And keep the same value until the next change to 00, so the date will change forward again.

I might need a help here again.

better still get a raspberry pi use python datetime
now=datetime.datetime.utcnow()+datetime.timedelta( hours=3)
and it does everything in one line

I'm thinking to get either a rasbery pi or arduino pro. I see all amature programmers goes there because coding and labraries are available everywhere.

I will try to picbasic pro here, but i dont understand why there is no categorized code and libraries available for doing our lifes easier, and with that way we also learn faster.

anyway as i said in the begging im an amature in programming and is not my main job. I do it on my spare time and i try to make as simple as possible.

[richard]

hh = hh +3
if hh>23 then
day_added = true
endif
hh = hh//24
.............

if day_added then
day = day +1
if day > numberofdayforthismonth then
day=1
month=month +1
if month >12 then
month=1
year=year+1
endif
endifendifendifendifendifendif lots of endifs

[astanapane]

hh = hh +3
if hh>23 then
day_added = true
endif
hh = hh//24
.............

if day_added then
day = day +1
if day > numberofdayforthismonth then
day=1
month=month +1
if month >12 then
month=1
year=year+1
endif
endifendifendifendifendifendif lots of endifs

Hi Richard that is really useful info. Now at this stage i have to make it work. I will set some vars first.

[richard]

anyway as i said in the begging im an amature in programming and is not my main job. I do it on my spare time and i try to make as simple as possible

you may think your way is as simple as possible but its not , its the hardest way by far.
my way breaks the task up into simple logical blocks , each task can then be solved independently ,and in isolation from the other tasks
the entire project can be built one task at a time

task1
read in nmea scentence
task2
verify crc
task3
identify scentence type
task 4
parse a GPRMC scentence

task4a
process a time field

task4b
process a LAT field
task4c
process a LON field

.....etc

simple small steps

[astanapane]

you may think your way is as simple as possible but its not , its the hardest way by far.
my way breaks the task up into simple logical blocks , each task can then be solved independently ,and in isolation from the other tasks
the entire project can be built one task at a time

task1
read in nmea scentence
task2
verify crc
task3
identify scentence type
task 4
parse a GPRMC scentence

task4a
process a time field

task4b
process a LAT field
task4c
process a LON field

.....etc

simple small steps

Ok if i cannot make it the way i have started, i will follow your advice, as given above.

[astanapane]

Hi Richard,

i think it is working. I need to test it one or two days....

I'll keep you updated because i need also to understand the "true" statement.

[astanapane]

Sorry forgot to upload the code.

The following is the one i have changed in order the date to change when the time is > 23

day_added = 0
hh = hh + 3
if  hh > 23 then
day_added = 1
endif
hh = hh//24
if day_added = 1 then
day = day + 1
if day > num_date then ; i havent done anything to this up to now. I need to figure out how to tell the programm about the num_date (No of the day today in this month)
day = 1
if month > 12 then
month = 1
year = year +1
    endif
      endif
        endif

regarding this

if day > num_date then ; i havent done anything to this up to now. I need to figure out how to tell the programm about the num_date (No of the day today in this month)

i think that i need to create a table with 12 months and specify which has 30, 31, or which year then has Feb 28 or 29

[richard]

the only thing I might add is that the conversion from utc to local time only needs to be done if and when the hour changes , its not needed in every loop.
a flag can be set when the utc hour now is != current utc hour , then the flag can be cleared when the conversion is done