BH1750FVI sample code available?

[CuriousOne]

Changed syntax, still getting zeroes, what I'm doing wrong?

ldta  var porta.6 
lclk  var porta.3        

x var word
y var byte
z var byte
cnt var byte 'control word
adr var byte
sda var portc.0
scl var portc.1
lcdout $fe, $01, " "
adr=$23
x=0

cnt=%0100011
i2cwrite ldta, lclk, cnt, adr
pause 200
cnt=%00010001
i2cwrite ldta, lclk, cnt, adr 
pause 200
maik:
cnt=%0100011
i2cread ldta, lclk, cnt, adr, x 
pause 200
lcdout $fe, $1, dec x
pause 200
goto maik

[Jerson]

1 - use the appropriate I2C address for the device based on the hardware pin state
2) Slave Address
Slave Address is 2 types, it is determined by ADDR Terminal
ADDR = ‘H’ ( ADDR ≧ 0.7VCC ) → “1011100“
ADDR = 'L' ( ADDR ≦ 0.3VCC ) → “0100011“

2 - the device address for case 1 is $B8 and case 2 is $46 (use one of these values in cnt)
When you put the address as shown in your code, the leading bit is 0 and the address will be $5c or $23. This is definitely wrong.

3 - cnt remains the same for I2CWrite and I2CRead. the least significant bit is changed internally by the compiler depending on whether the command is a read or write

[CuriousOne]

Thanks!
Tried both, none works, so I guess, I'm missing something else too...

[Jerson]

You ought to be sending this way

Assuming ADDR pin is low

    i2cwrite ldta, lclk, $46, adr,  dat

and read by

    i2cread ldat, lclk, $46, adr, dat

make sure the adr and dat match with the register of the device and dat relevant to the register. It should work.

[richard]

You ought to be sending this way

not in my view
addr var byte
addr= $46
i2cwrite sda,sck,addr,[opecode]
i2cread sda,sck,addr,[dat.highbyte,dat.lowbyte]

[CuriousOne]

Big thanks Richard! now it works!

here's the code:

adr=$46
x=0
cnt=%0100011
i2cwrite ldta, lclk, adr, cnt
pause 200
cnt=%00010001
i2cwrite ldta, lclk, adr, cnt 
pause 200
maik:
cnt=%00010001
i2cwrite ldta, lclk, adr, cnt 
pause 200
cnt=%0100011
i2cread ldta, lclk, adr, [x.highbyte, x.lowbyte] 
pause 200
lcdout $fe, $1, dec x
pause 200
goto maik

[richard]

Big thanks Richard! now it works!

as maybe but you are still incorrect , if you use a logic analyzer you will see the transaction ends abnormally



wrong way
i2cwrite ldta, lclk, adr, cnt
correct way
i2cwrite ldta, lclk, adr, [ cnt ]