I believe most pic16's and PIC18's have a 20mA source or sink limit so a resistor on the pin would not be required.
So FromTheCockpit's diagram above will work, though you will not get 5V to feed the LED so you'll need to trim the LED's resistor if you want a brighter LED.

Also on that note... an LED consumes more than 20mA (~33mA at desired voltage i believe) so... you may not need a resistor on the LED. Instead, if you up the voltage divider resistance values ~ 2K each the LED would not come on but you would still have your /2 voltage divider.