That explained A LOT !
now it all makes sense
thanks a lot for your help this couldn't be explained any better![]()
That explained A LOT !
now it all makes sense
thanks a lot for your help this couldn't be explained any better![]()
but shouldn't it be "Fosc/4" if I'm using (1:1) prescale ? (1MHz/4 in our case ) which gives PWM frequency 1655Hz ?
Hi,
Note that I said - If the timer is driven with a frequency of 1MHz - which it would be if you run the PIC at 4MHz and select Fosc/4 as the PWM Timebase input.
Apart from that you are correct. If you'd run the PIC at 1MHz and set the PWM timebase to derive it's clock from Fosc/4 then the timebase will run at 250kHz and you'd get a PWM frequency of 1655.5Hz with the values in the previous example.
/Henrik.
My bad
Once again Thanks Henrik
Last two questions (I hope so )
in Bruce's Example he's multiplying pdcx by (Lowbyte,Highbyte) Low and high byte of what and what is the purpose of doing that ?
also
anyway I'm going to post the Code since I can't find the problem yet .. what I'm Trying to do is to generate a sinewave from pwm0 with an offset to use that later in a three phase inverter.. so I made this test which gives unexpected results
what I'm trying to do is using entries from a lookup table to generate pulses with duty cycles starting from 1000 to 2000 then back to 1000 (Positive half Cycle) after that going from 1000 to 0 and going back again to 1000 (Negative half Cycle) which isn't happening ..
I'm using 10MHz osc 18f4431, and a lookup table of 25 Entries (Which isn't enough for a smooth wave but this is for testing)
ThanksCode:PORTB = 0 TRISB = %11000000 ' pwm0-5 output PTCON0 = %00000000 ' (1:1) prescale , Free-Running mode PTCON1 = %10000000 'time base is on, Counting is up PWMCON0 = %01000000 'Pwm0-5 enbbled for pwm output, pwm0-5 complementary mode PWMCON1 = %00000001 OVDCOND = %11111111 PTPERL = $D0 PTPERH = $07 'PTPER = 2000 Main: PDC0L = 00 PDC0H = 10 PDC0L = 59 PDC0H = 12 PDC0L = 00 PDC0H = 15 PDC0L = 07 PDC0H = 17 PDC0L = 66 PDC0H = 18 PDC0L = 66 PDC0H = 19 PDC0L = 00 PDC0H = 20 PDC0L = 66 PDC0H = 19 PDC0L = 66 PDC0H = 18 PDC0L = 07 PDC0H = 17 PDC0L = 00 PDC0H = 15 PDC0L = 59 PDC0H = 12 PDC0L = 00 PDC0H = 10 PDC0L = 41 PDC0H = 07 PDC0L = 00 PDC0H = 05 PDC0L = 93 PDC0H = 02 PDC0L = 34 PDC0H = 01 PDC0L = 34 PDC0H = 00 PDC0L = 00 PDC0H = 00 PDC0L = 34 PDC0H = 00 PDC0L = 34 PDC0H = 01 PDC0L = 93 PDC0H = 02 PDC0L = 00 PDC0H = 05 PDC0L = 41 PDC0H = 07 PDC0L = 00 PDC0H = 10 GoTo Main
Last edited by Kloney; - 4th July 2013 at 08:19.
Hi,
You are currently updating the dutycycle register at a very fast rate, much much faster than the PWM frequency. Try insterting a short delay ( PAUSE 5 or whatever) between each duty cycle update. If that doesn't help try explaining what it does and what the problem is.
I'll have to look at Bruce's example to see if I can answer the other (first) question.
/Henrik.
EDIT: OK, looked at Bruce's example but I don't see where he's multiplying the pdcx with anything....could you clarify?
Last edited by HenrikOlsson; - 4th July 2013 at 11:12.
I added a "1 us" delay and it worked quite well but the wave took longer duration time, the output frequency is 16.6hz instead of 50hz becaus of the delay
I'm using 25 entry and the output should be 50hz (Fpwm = 50 * 25 = 1250 I guess ?) how can I fix that ?
Also for the DTCON I can't get this part I need a 5us dead-time and I'm using (Fosc/4) settings what are the calculations needed for "5-0" bits in DTCON to set such a dead-time ?
For Bruce's Example this is the part I'm talking about :
Duty = 800 ' ~50% PDC2L = Duty.LowByte ' maintain a fixed 50% duty cycle on PWM4,5 PDC2H = Duty.HighByte
But i don't think that I'm going to need that in my case I just was wondering to understand the whole thing what are the LowByte and HighByte ?
Thanks Henrick , I can't find words to describe how much you helped me
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