Inverse of COS

[uuq1]

Can anybody help me find ArcCos?

Regards,
uuq

[Dwayne]

Hello uug1,

In order to do this, you must use the taylor series..

Go to the bottom of this link... IT gives a LOT of info.

http://www.picbasic.co.uk/forum/show...ghlight=Taylor

Dwayne

[bot402]

Alternatively, look at the PROTON+ compiler.

This does true floating point calculations including trigonometry.

[uuq1]

I tried with Taylor series but no good.
For angles less than 45 degrees, the code seem to work ok, but for larger angles the deviation is high.

I have decided to use interpolation with select.

Appreciate the help I got from this place.

[languer]

You may also want to look here:
http://www.emesys.com/BS2math3.htm

[uuq1]

Thanks languer for the article. I think it will help.