The New_Bits will be the same for A & B, but the Old_Bits should still have PORTA.0 (B pin of encoder) as 1 for the last falling edge interrupt, won't it?
The New_Bits will be the same for A & B, but the Old_Bits should still have PORTA.0 (B pin of encoder) as 1 for the last falling edge interrupt, won't it?
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