Hi,
Print the page 3 and 4 of the CJ120 PDF.
(The Block diagram page and the Application circuit page).
http://www.semiconductors.bosch.de/p...y_extended.pdf
Add to the application circuit the two op-amp's and connect them
as they are depicted on the block diagram page.
(Draw that with a pencil inside the CJ120 on page 4).
The two op-amp's:
Pumpstrom-Regler = Pump current control
Pumpstrom-Meßverstärker = Pump current sense amplifier
Voltages:
==============================================
PIN Vcc = +5 V
==============================================
PIN VM = +2.5 V (Virtual ground voltage source)
(0.5 x VCC)
==============================================
PIN US = +2.95 V (Nernst cell reference voltage source)
(450mV, reference to virtual ground)
===============================================
PIN GND = 0 V
================================================
The two op-amp's have a single polarity supply.
(+5 and GND).
On the output of the op-amp "Pump current control"
you will need a 100 ohm resistor.
* * *
The idea is to replicate what Bosch is doing inside the CJ120.
You will need a way to simulate the LSU4 during the testing of the circuit.
(DC +/- milliampere meter and a voltage that goes from 4.0V down to 2.5).
Do you understand how it works?
Luciano
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