Henrik,
What "low order bits" means in this case is that "\X" will always shift out the x lowest bits. So myByte\4 or myWord\4 or myLong\4 would all just output the 4 lowest bits. Now that the correct bits have been determined, it will shift them out based on the mode. So you can think of "\X" as "Shift out the lowest X bits of the variable"

This is why I'm curious about the actual output of the the shift statement used, which could be understood as, "Shift out the lowest 24 bits in the byte called myArray". As you can see, it doesn't make a lot of sense, but it's going to try to do something, and I am wondering what that something is.