Hi, I've done several projects in the past using phase fired control to dim AC loads. I've always used 2 diodes from the supply transformer to give me a DC ripple then a 10K resistor to connect that into a PIC and a 100K pull-down resistor. I'm now making a new project using a PIC24FJ64GA002 which operates at 3.3V rather than 5V. When designing the circuit I realised that I've just been using 10K and 100K without giving any thought as to why and that they might not be suitable for lower voltage PICs.
Is there a calculation I can use to figure out what value the resistors should be based on the supply voltage and the maximum voltage/current rating of the PIC pins?
Bookmarks