Strange Behavior in setting several pin outputs states.


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  1. #1
    Join Date
    Dec 2011
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    Default Re: Strange Behavior in setting several pin outputs states.

    Yes, I am using your shadow method, but it only works with adding pauses this way:

    PORTC.0 = 1
    PAUSE 10
    PORTC.1 = 1
    PAUSE 10
    PORTC.2 = 1
    PAUSE 10
    PORTC.3 = 1

    If I remove the pauses, then the thing does not work...

    Thank you very much again.

  2. #2
    Join Date
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    Default Re: Strange Behavior in setting several pin outputs states.

    What if you did it like this?
    Code:
     ShadowC VAR byte
     ShadowC = PORTC
    
     ShadowC.0 = 1
     PORTC = ShadowC
    
     ShadowC.1 = 1
     PORTC = ShadowC
    
     ShadowC.2 = 1
     PORTC = ShadowC
    
     ShadowC.3 = 1
     PORTC = ShadowC
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  3. #3
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    Default Re: Strange Behavior in setting several pin outputs states.

    I want to thank you very much.

    The problem is resolved, now I am setting the pin output states super fast!

    The final working code was the one posted by rmteo, but thank you all really!


    ShadowC VAR byte
    ShadowC = PORTC

    ShadowC.0 = 1
    PORTC = ShadowC

    ShadowC.1 = 1
    PORTC = ShadowC

    ShadowC.2 = 1
    PORTC = ShadowC

    ShadowC.3 = 1
    PORTC = ShadowC

  4. #4
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    Default Re: Strange Behavior in setting several pin outputs states.

    You can do it even faster by doing it the way Charles originally showed you, (did you REALLY try that and it didn't work?) in other words:
    Code:
    ShadowC VAR BYTE
    ShadowC = PortC
    
    ShadowC.0=1
    ShadowC.1=1
    ShadowC.2=1
    ShadowC.3=1
    
    PortC = ShadowC
    /Henrik.

  5. #5
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    Default Re: Strange Behavior in setting several pin outputs states.

    Quote Originally Posted by HenrikOlsson View Post
    You can do it even faster by doing it the way Charles originally showed you, (did you REALLY try that and it didn't work?) in other words:
    Code:
    ShadowC VAR BYTE
    ShadowC = PortC
    
    ShadowC.0=1
    ShadowC.1=1
    ShadowC.2=1
    ShadowC.3=1
    
    PortC = ShadowC
    /Henrik.
    Even faster would be this way - but obviously the OP did not try it the way Charles described.
    Code:
    ShadowC VAR BYTE
    ShadowC = PortC
    
    ShadowC.0 = $F
    
    PortC = ShadowC
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  6. #6
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    Default Re: Strange Behavior in setting several pin outputs states.

    Sorry for the typo - and the inability to edit a post.

    Code:
    ShadowC VAR BYTE 
    ShadowC = PortC  
    
    ShadowC = $f 
    
    PortC = ShadowC
    Why pay for overpriced toys when you can have
    professional grade tools for FREE!!!

  7. #7
    Join Date
    Oct 2005
    Location
    Sweden
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    Default Re: Strange Behavior in setting several pin outputs states.

    Hi,
    Even faster would be this way - but obviously the OP did not try it the way Charles described.
    Not really because then the top four bits will be 0 which they might not have been when PortC was read. And IF the top four bits doesn't matter then I see no reason for not simply writing to PortC directly, ie PortC = $F which would make THIS particular example even faster....

    However, I suspect that setting the low four bits to 1 are just an example. Using bitwise AND/OR could also work but I'm not sure it's faster than simply flipping the four bits in ShadowC and then writing it to the port.

    /Henrik.

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