Measurement time of a peace of code

[HenrikOlsson]

Hi,
I just use a timer.

Time VAR WORD
 
TMR1L = 0
TMR1H = 0
 
T1CON.0 = 1  'Start TMR1
'code here
'code here
T1CON.0 = 0  'Stop TMR1
 
Time.HighByte = TMR1H
Time.LowByte = TMR1L
HSEROUT ["Execution time in cycles: ", DEC Time,13]

Something like that though I'm sure I've missed a bracket somewhere.... :-)

/Henrik.

[mister_e]

MPLAB stopwatch also do the trick pretty well

If you have a Scope, set a pin high before the section of code you want measure, and clear it at thye end. not as accurate as Timer or StopWatch but easy easy easy

[gadelhas]

Something like that though I'm sure I've missed a bracket somewhere.... :-)

Ehehe, this time i don't think so!!! Can you tell me hoe do i do the math so i can have a value in seconds or miliseconds.
I'm using a 8Mhz osc, so with Fosc/a i get 2Mhz, so 0.5uS for cycle. I must multiply this value for the value that i've got in the time var?
Thank you Henrik

MPLAB stopwatch also do the trick pretty well

If you have a Scope, set a pin high before the section of code you want measure, and clear it at thye end. not as accurate as Timer or StopWatch but easy easy easy

I'm using MCS, i'm not used to use MPLAB, i think that way with the scope its better. Thank you Steve

[gadelhas]

Update;

I made this code

Main:
    if Bmais = 0 then 
        pause 50   
        Time VAR WORD
        TMR1L = 0
        TMR1H = 0
        T1CON.0 = 1  'Start TMR1
        'Inserir rotina a medir
            GOSUB PI
        T1CON.0 = 0  'Stop TMR1
        Time.HighByte = TMR1H
        Time.LowByte = TMR1L
    ENDIF
    
    lcdout $FE, 1, " Medidor ciclos "
    lcdout $FE,$C0,"N. Ciclos: ", #time
    Pause 100
GOTO Main

When i press Bmais, i get always 7203 cycles, so multiply by 0.5uS, i get 0.003602 S, or 3.6mS. Is this calculations correct?

[mister_e]

maybe... replace the gosub by a pause 10, and see what happen

[gadelhas]

maybe... replace the gosub by a pause 10, and see what happen

I get always 20009 cycles, so multiply by 0.5uS, i get 0.010005S, or 10mS. So i assume that is correct, and works great.

Thank you Henrik and Steve!

[HenrikOlsson]

Yes exactly, in this case it's just a matter of multiplying the value you get with 0.5 to get the answer in uS.

If you want to do that in PBP then perhaps:

' In us
LCDOUT $FE, 1, ["Timer ticks: ", DEC Time]
LCDOUT $FE, $C0, ["Execution time: ", DEC Time/2, "." DEC Time//2, "us",13]

I think that should do it.

[Bruce]

DT has a nice example here: http://www.picbasic.co.uk/forum/show...=1272#post1272

Something else to consider is where the code you're timing is located. See the 1st paragraph.

[gadelhas]

I got it. Thank you all, once again!