Most devices sink current much more readily than they source current. My guess is that if you connected the + side of the relay to 3.3V and the - side to your PIC pin, the PIC would drive the relay perfectly.
Most devices sink current much more readily than they source current. My guess is that if you connected the + side of the relay to 3.3V and the - side to your PIC pin, the PIC would drive the relay perfectly.
Charles Linquist
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