Mcp3208 adc help

[shawn]

Ok
I tried that also and it is a no go. Am I reading the result to fast with the shift in command and the hold cap is not charging. I've read the data sheet numberous times now and can't figure this out. The protocol for the mcp3208 looks the same as the mcp3202. Or am I wrong. I am lost.
Thanks
Nick

[cncmachineguy]

So in essence, you are losing bit 11 and 12 from your result. Although at 5V, one would expect a result of 4095. Anyway, are you sure you are following all the clocking rules as outlined in section 6? I have not read it enough to fully grasp it, but it seems like you may have a clocking after the start bit issue.

[shawn]

OK, Learning time Steve. For me that is. I read through your post to fast sorry I am always on the go. When I added the fifth bit to my shiftout command I did not get the right result but I did get a different result. I got 2047 when I applied 5V to the input. So then Bert said that it looks like I am missing the 11 or 12 bit, and I agree. So I added a 6th bit to the shiftout command. And I got a very strange result. My value turned to zero. I was using input 0, but at this point I thought I would try the other inputs to see if they were reacting because they are all tied to ground except input 0. Turns out that input 4 was now being used and guess what, when I applied 5V to it, it returned 4095. So here is my vague question what the heck is going on? The data sheet for the MCP3208 needs a 4 bit command MSBF.
First Bit is mode
Last Three Bits is the analog input selection


So I originally tried this.
SHIFTOUT DataOut, Clock, MSBFIRST, [%1000\4] ' Select CH0, Single-Ended
My result bounced from 1023 to 3047 on input 0.


Then Steve said to try this.
SHIFTOUT DataOut, Clock, MSBFIRST, [%11000\5] ' Select CH0, Single-Ended
My result then was 2047 on input 0, it appears that I am missing the 12 bit like Bert said.


Then I tried this.
SHIFTOUT DataOut, Clock, MSBFIRST, [%111000\6] ' Select CH0, Single-Ended
My result was 0 but input 0 was tied to 5V. I found that the command had changed my input to input 4. And it was tied to ground. When I tied it to 5V I got my 4095 result like I anticipated.


Then I tried this.
SHIFTOUT DataOut, Clock, MSBFIRST, [%110001\6] ' Select CH0, Single-Ended
My result was input 0 4095 with 5V applied. I don't understand this. Its like the MCP3208 chip drops the first and last bit I shiftout to it. I don't see why that works in the data sheet. Could someone explain it to me? I could understand adding the extra bits to one side or the other but not both.
Also is there a way to do this with a delay instead of extra bits in my command, it seems a bit cobbled.
I see this command(DEFINE SHIFT_PAUSEUS 100) in the PBP Manual but it just looks like it will slow my clock speed, which I don't think would be good.

Thanks
Shawn

[cncmachineguy]

The way I read the sheet, its not a delay thing. Seems like the A/D uses the SCL to clock the result out, starting some number of clocks after the start bit. So no matter what you do, on the 12th(maybe wrong number, working from memory here)clock, data is comming out. better be ready to catch it. When you "shiftout" the command, thst starts the clock counting. that gives you start bit, then 4 more clocks (i think) then data is comming on the something more clock.

I will need to re-read section 6 to try and wrap my head around it. Let me know if you need more info, I will read some more.

[mister_e]

That seems odd but I'm rusty, so I've ordered a couple of those ADCs. Should have them tomorrow.

Another thing you could try (though I may need another strong coffee)... keep your original code, but read the data on clock falling edge instead of rising edge.

[mister_e]

Duh?!?

3.6 Serial Data Output (DOUT)
The SPI serial data output pin is used to shift out the
results of the A/D conversion. Data will always change
on the falling edge of each clock as the conversion
takes place.

Change your clock idle from low to high, and see what happen.

[mister_e]

That was easy

        high cs
        Pause 100 ' Pause to see display on LCD.
Main:
        LOW CS ' Enable ADC
        SHIFTOUT DataOut, Clock, 2, [%11000] ' Select CH0, Single-Ended
        high Clock
        SHIFTIN DataIn, Clock, 6, [result0\13] ' Read ADC
        HIGH CS ' Disable ADC
        Low Clock
        LCDOUT $FE,1,"ADC: ",dec result0
        PAUSE 100 'Pause long enough to read LCD.
        Goto Main

now read the datasheet to know why it works