16F1827 voltage issue


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    According to my calc, to run LED's from 5V source you will need ~85 Ohm resisters in series for each led between the LED annode and the pic IO port to reduce the current down to 20mA each...
    Thats assuming the LED's have a drive voltage of 3.3V

    to work it out...
    5 - 3.3 = 1.7V diference

    now use V=IR re-aranged to R=V/I

    Where,
    V = voltage diference
    I = Current in amps (mA is 1/1000A or 0.001A)
    R = Resistance in ohms
    Last edited by comwarrior; - 27th January 2011 at 22:51.

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