Maximum value of ADCIN

[Darrel Taylor]

No, that won't matter.

Can you post your Proteus files (zipped)?

[fratello]

Yes, all is OK now !
If v_cal is 1023 (maximum 5.000V) it's correct this command for memorise in EEPROM :
write 0, v_cal
I read the PBP help, but I find only this : write 5,B0 ' Send value in B0 to EEPROM location 5.
And I can read them when I need, with this command :
read 0, v_cal ???
It's enough like these or need more ?
Thanks in advance and sorry for my ignorance...

[Darrel Taylor]

If v_cal is 1023 (maximum 5.000V) it's correct this command for memorise in EEPROM :
write 0, v_cal
...
read 0, v_cal ???
It's enough like these or need more ?

If you have PBP 2.60, then you could ...

write 0, WORD v_cal

read  0, WORD v_cal

If you don't have 2.60 yet, you'll need to ...

write 0, v_cal.LowByte
write 1, v_cal.HighByte

read  0, v_cal.LowByte
read  1, v_cal.HighByte

[fratello]

I understand now ; I read 10 pages of search "eeprom".
Of course, the answer it's simple if somebody help ! Thanks, Mr.Darrel !
....
So, if eeprom it's like in picture :
75 (hex) = 117 (dec)
v_cal = 117 * 4,8875 = 572 mVolts ?

[Darrel Taylor]

So, if eeprom it's like in picture :
75 (hex) = 117 (dec)
v_cal = 117 * 4,8875 = 572 mVolts ?

Yes, if you saved the MAX A/D value instead of the converted value.

In that case, be sure to use the previous formula to convert it to voltage.

v_cal=v_cal * 5000            ' I use VDD as Vref
v_cal=div32 1023.

[fratello]

I use this code :

    vmax = 0
    for cnt =1 to 70       			
        adcin 3, v_cal
        vmax =vmax max v_cal
        pause 100
    next cnt

    v_cal=vmax * 5000            ' I use VDD as Vref
    v_cal=div32 1023

write 0, v_cal.LowByte
pause 10
write 1, v_cal.HighByte
pause 10

[Darrel Taylor]

Then you have saved the value as a Voltage.
And 117 means 117mV.

Since I = E / R ... with a 0.02 ohm resistor ...

0.117 / 0.02 = 5.85 Amps

Dividing by 0.02 is the same as multiplying times 50.

117 * 50 = 5850 or 5.850 Amps.