Oops, disregard my comment. Yes, you should get your result in millivolts.
Robert
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Oops, disregard my comment. Yes, you should get your result in millivolts.
Robert
"No one is completely worthless. They can always serve as a bad example."
Anonymous
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Tested and re-tested today both variant : Mr.Darrel's and Mr.Aratti.
Still different results : 5mV vs. 24 mV. It's so strange for me...
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fratello,
I'm not sure what you've done in your code, but I've tested it here and it works.
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DT
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Wow, Thank You again Mr.Darrel !
Maybe my code it's wrong ; I use
insteadCode:DEFINE OSC 4 DEFINE ADC_BITS 10 DEFINE ADC_CLOCK 3 DEFINE ADC_SAMPLEUS 50
This is the explanation, don't ?Code:DEFINE ADC_BITS 10 ' ADCIN resolution (Bits) DEFINE ADC_CLOCK 1 ' ADC clock source (Fosc/8) DEFINE ADC_SAMPLEUS 11 ' ADC sampling time (uSec)
NO, I think this is NOT the explanation ! My math teacher it's verry, verry angry...
I learn more here : http://www.darreltaylor.com/DT_Analog/
1 step=0.0048875. So, if I have Max_result 450, Volts= 450 * 0.0048875 =2.199 Volts; for 696 --> Volts= 696 * 0.0048875 =3.401 Volts...
Stupid me, again
Last edited by fratello; - 13th November 2010 at 16:54.
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No, that won't matter.
Can you post your Proteus files (zipped)?
DT
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Yes, all is OK now !
If v_cal is 1023 (maximum 5.000V) it's correct this command for memorise in EEPROM :
write 0, v_cal
I read the PBP help, but I find only this : write 5,B0 ' Send value in B0 to EEPROM location 5.
And I can read them when I need, with this command :
read 0, v_cal ???
It's enough like these or need more ?
Thanks in advance and sorry for my ignorance...
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If you have PBP 2.60, then you could ...If v_cal is 1023 (maximum 5.000V) it's correct this command for memorise in EEPROM :
write 0, v_cal
...
read 0, v_cal ???
It's enough like these or need more ?
If you don't have 2.60 yet, you'll need to ...Code:write 0, WORD v_cal read 0, WORD v_cal
Code:write 0, v_cal.LowByte write 1, v_cal.HighByte read 0, v_cal.LowByte read 1, v_cal.HighByte
DT
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