Hi;
Try this;
1 - Connect the RA4 Pin with the resistor to VCC;
2 - Connect the anode of the led beetwen the resistor and the RA4 Pin;
3 - Connect the Cathode of the led to GND
And post the result
Hi;
Try this;
1 - Connect the RA4 Pin with the resistor to VCC;
2 - Connect the anode of the led beetwen the resistor and the RA4 Pin;
3 - Connect the Cathode of the led to GND
And post the result
Thanks and Regards;
Gadelhas
The reason that you need a resistor between RA4 and Vcc, like Gadelhas mentioned above, is because RA4 in that chip is an Open Drain (OD) type.
Robert
"No one is completely worthless. They can always serve as a bad example."
Anonymous
Sorry about the delay getting back to ya'll. Ok, your instructions said:
1 - Connect the RA4 Pin with the resistor to VCC;
2 - Connect the anode of the led beetwen the resistor and the RA4 Pin;
3 - Connect the Cathode of the led to GND
with or without step 2 the led is illuminated.
Thanks for the fast response.
RA4 is C2OUT with the 1st configuration you had so you couldn't use it for a digital output. With comparators disabled you can.
This should work fine to drive your LED on RA4 ---|<|---/\/\/--VCC.
Bruce, thats how I have it, However, I have brown out reset enable on my winpic programmer software, tried it with PICkit3, PICkit2 and it won't work, BUT if I turn off the brown out reset manually in WINPIC programmer, It WORKS
But I am going from 9v input to my breadboard, then LP2950ACZ-3.3 (3.3V) regulator to my processor, sure would be nice to use the low voltage (brown out).
Any ideas?
Thanks
If turning an LED on is tripping reset you might want a larger cap on the reg output or larger series resistor for the LED. BOR definitely shouldn't trip unless you're dropping a lot of power.
Edit: Check the datasheet for Vbor. You may already be running marginal.
Last edited by Bruce; - 24th August 2010 at 22:46.
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