LTC2400 SPI interface

[HenrikOlsson]

how to feed 1v? is that any voltage regulator available for 1v.what about the -ve side.

Well, anyway you like really. The simplest way is a voltage divider but then the stability and accuracy of you reading depends on the stability of the powersupply rail, which it does when you're using the Vdd/Vss for Vref anyway.

The voltage supplied to Vref- is what will equal a returned value of 0 from the ADC, the voltage supplied to VRef+ is what will equal a returned value of 1023 from the ADC. So by feeding 1V to Vref- and 5V to Vref+ the ADC's 10 bits gets divided across 1-5V instead of 0-5V as is the case when you use Vss/Vdd as reference. (As long as you use 5V supply of course). Read up on the ADC section of the datasheet for details about the ADC.

I can't help with your problem as I have absolutely no idea how you've coded it.

/Henrik.

[PUGALENTHI.P]

Well, anyway you like really. The simplest way is a voltage divider but then the stability and accuracy of you reading depends on the stability of the powersupply rail, which it does when you're using the Vdd/Vss for Vref anyway.

The voltage supplied to Vref- is what will equal a returned value of 0 from the ADC, the voltage supplied to VRef+ is what will equal a returned value of 1023 from the ADC. So by feeding 1V to Vref- and 5V to Vref+ the ADC's 10 bits gets divided across 1-5V instead of 0-5V as is the case when you use Vss/Vdd as reference. (As long as you use 5V supply of course). Read up on the ADC section of the datasheet for details about the ADC.

I can't help with your problem as I have absolutely no idea how you've coded it.

/Henrik.

As you said i looked at the pins and i cant find any -vref.

"The positive voltage reference can be either VDD or an external voltage source. The negative voltage reference is always connected to the ground reference" this is what i found on the datasheet.

THANKS and REGARDS,
PUGAL

[HenrikOlsson]

Hi,
If that what it says then that's how it is. I didn't check the datasheet and I've never personally used a PIC where only the +Vref is available. Now I know they exist as well, thank you!

Then it gets trickier, one way is to use some analog circuitry to first subtracst 1V from the signal and then amplify it with a gain 1.25, that will give you 0-5V output. An easier way is probably to get a PIC which has it's -Vref available to the outside.

There are IC's available specifically for converting current loops to voltage, here's a MAXIM app note showing one.

But again, what kind of resolution do you really need? Do you have a datasheet for the transducer you're using?

/Henrik.

[PUGALENTHI.P]

Hi,
If that what it says then that's how it is. I didn't check the datasheet and I've never personally used a PIC where only the +Vref is available. Now I know they exist as well, thank you!

Then it gets trickier, one way is to use some analog circuitry to first subtracst 1V from the signal and then amplify it with a gain 1.25, that will give you 0-5V output. An easier way is probably to get a PIC which has it's -Vref available to the outside.

There are IC's available specifically for converting current loops to voltage, here's a MAXIM app note showing one.

But again, what kind of resolution do you really need? Do you have a datasheet for the transducer you're using?

/Henrik.

hai HENRIK,

THANKS FOR YOUR KIND HELP.For now i don't have the datasheet,but give some time ill find the datasheet and forward to you.Actually i want to read the 4-20 mA from a transduser with the accuracy of 0.1% and the resolution is 0.0000,the transduser has the accuracy of 0.05% and the range is 0-100,000psi this the maximum that we have.so if i manage to do the project,then i can use the same for all the other transduser with better accuracy.some are 0-5v and few are 0-10v which will be easy to do as you said.

THANKS and REGARDS,
PUGAL.

[HenrikOlsson]

Hi,
I'm not following you on the resolution. You say the transducer measures 0-100000 PSI with a resolution of 0.0001 PSI? That's 1.000.000.000 "counts" across the 16mA output swing - WOW!

I mean, even at 1 PSI "per count" the difference in output current is 0.016/100000=0.16uA. Push that thru your 250ohm resistor and you get a voltage change of 40uV per PSI - that's not a lot.

If you mean 100PSI then it gets a little more managable as 1PSI now eqauls a change in current of 160uA and a voltage change across the resistor of 40mV.

/Henrik.

[PUGALENTHI.P]

Hi,
I'm not following you on the resolution. You say the transducer measures 0-100000 PSI with a resolution of 0.0001 PSI? That's 1.000.000.000 "counts" across the 16mA output swing - WOW!

I mean, even at 1 PSI "per count" the difference in output current is 0.016/100000=0.16uA. Push that thru your 250ohm resistor and you get a voltage change of 40uV per PSI - that's not a lot.

If you mean 100PSI then it gets a little more managable as 1PSI now eqauls a change in current of 160uA and a voltage change across the resistor of 40mV.

/Henrik.

THANKS FOR YOUR REPLY


Sorry, actually the circuit must support wide ranges of transduser so that for low range transduers like 0~100 mbar and mid range transdusers like 0~500 bar it must have 0.0000 resolution and for high pressure transdusers as i said before like 0~100,000 it must have the accuracy of 0.1% and no need to worry about the resolution. so the circuit must have the capability to measure as much as possible.but for now i used the over sampling method and i got the accuracy of 0.1% for 0~100,000 psi on 10 bit internal adc which is my first stepping stone with the valuable help from MR.Henrik and thanks a lot for that.

THANKS and REGARDS,
PUGAL.