Thanks Mike.
Nope, not even a +=Originally Posted by Mike, K8LH
However, your x = (x+1)&7 takes much less time than my x = (x + 1) // 8 (Modulus) approach.
What was I thinking?
Cool, thanks!
|
Thanks Mike.
Nope, not even a +=
However, your x = (x+1)&7 takes much less time than my x = (x + 1) // 8 (Modulus) approach.
What was I thinking?
Cool, thanks!
DT
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