Troubles with I2C_Write

[The Altruist]

While I have your attention, I'm puzzling over how to efficiently do a 10-bit by 10-bit division (which will yield a value 0<x<1) then multiply it again by 1023 to get a number (0<=x<=1023). I'd prefer not to use LONG values as they eat up precious RAM, but I also want to keep it reasonably quick. I have plenty of words set up, but no LONGs.
Here's the math:
a, b, and x are WORDs
x=1023*(a-b)/(a+b)
Any thoughts?
EDIT: Oh. Ha ha. I don't even have LONGs to work with. Yeah... that makes a difference now, doesn't it?
The only thing I can conceive of is using a two-fold mechanism that combines this:

'Shift RESULT left 10 times
FOR Iter=1 to 10
	RESULT=RESULT<<1
NEXT

with this:

'RESULT= B / A
RESULT=0
WHILE B>A
	B=B-A
	RESULT=RESULT+1
WEND

The trick is to keep the working value inside 16-bits, but inside 10 bits at the very end.

[The Altruist]

For those of you wondering, this algorithm gives decently accurate 10-bit ratios with a Big O of (n^2). I hope some one finds it useful.
Bear in mind that the Numerator MUST be smaller than the Denominator, and that the denominator bit-shifted left to be bigger than the Power of 2 you're trying to fit it in. Therefore, don't change the 1024 to 16384 and expect it to work (while still using 16-bit WORDs).

TenBitRatio:
		Result=0
		while Denominator<1024 
			Numerator=Numerator<<1
			Denominator=Denominator<<1
		WEND
		while	Denominator>0
			Digit=0
			while	Numerator>Denominator
				Numerator	=	Numerator	-	Denominator
				Digit=Digit+1
			WEND
			Denominator	=	Denominator>>1
			Result	=	Result	<<	1
			Result	=	Result	+	Digit
		WEND