Continueous ADC scanning using DT interupts

[comwarrior]

i've just spotted this bit...

Figure 21-5 shows the operation of the A/D converter
after the GO/DONE bit has been set, the
ACQT2:ACQT0 bits are set to ‘010’ and selecting a
4 TAD acquisition time before the conversion starts.

Which indicates that the program doesn't need to execute a wait before 'hitting go'...

[mackrackit]

And later it tells you this

After the A/D conversion is completed or aborted, a
2 TAD wait is required before the next acquisition can be
started. After this wait, acquisition on the selected
channel is automatically started.

Look at Figure 21-1, all of the ANX's go to the same converter. Needs a little time between reads...

[comwarrior]

I must be awake now because it's starting to make sense...
I hadn't spotted the bit that allows manual acquisition... but in normal mode will do the acquisition automatically before the conversion.
And that's what was confusing me...

[shakes head] seems obvious now...

Thanks for the help

[JohnMacklo]

Try to do this. I have been used this for a while, and it works fine for my purposes.

Loop:
gosub LeeEntradaAnalogica ' calls to subroutine LeeEntradaAnalogica".
goto Lazo
end



LeeEntradaAnalogica:
Auxiliar = 0
For J1 = 0 To 9
ADCIN H2, Auxiliar ' Guarda el valor del canal analógico en la variable "Auxiliar"
AnlgInput[H2] = AnlgInput[H2] + Auxiliar
for J2 = 0 to 50
pause 1
next J2
Next J1
AnlgInput[H2] = (AnlgInput[H2] /10) ' Divide el valor de Canal[H2] entre 10 para obtener un promedio.
If AnlgInput[H2] < 0 Then ' Si el valor obtenido es menor que 0.
AnlgInput[H2] = 0 ' significa que el valor leido en el canal no es real.
EndIf
If AnlgInput[H2] > 1023 Then ' Si el valor obtenido es mayor que 1023.
AnlgInput[H2] = 1023 ' significa que el valor leido en el canal no es real.
EndIf
Return

I think the comments don't matter. sorry but I think in spanish.
By the way, this piece of code is embedded in a program that uses DT interrupts. Darrel Taylor Rules!