If I reset the timer I will obviously always get the same value because temp will always display the same value.
So I rewrote the code to this:
Code:
staticVal var word
temp VAR word
TMR1H=0 ' Reset timer value
TMR1L=0

T1CON.0=1 ' start the timer
pauseus 1000
T1CON.0=0 ' Stop the timer

staticVal = 70
T1CON.0=1 ' start the timer
LCDOUT $FE,$80,"TMR1 = ", dec staticVal
T1CON.0=0 ' Stop the timer
temp.HighByte=TMR1H
temp.LowByte=TMR1L
LCDOUT $FE,$C0,"Disp Time = ", dec temp
and I specified different values to display in staticVal.
It turns out that displaying 1 to 9 took 3819 ms
to display 10 to 29 and 40 to 49 took 3944 ms
to display 30 to 39 and 50 to 69 took 3938 ms
and so on...

So you are right, this confirms that the difference of time LCDOUT is taking to display is based on which value is beeing displayed. This makes me wonder because technically it is always computing 4 bit at a time but at least now I know what is going on and I thank you for your help and your patience.

Mike