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  1. #33
    Join Date
    Feb 2010
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    I live in the UK
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    Hi Henrik,

    Yes, NOT GATE or inverted output, here's a Wiki link for any other newbies:

    http://en.wikipedia.org/wiki/Inverter_(logic_gate)

    Like I said in my post above, it's easy to jump to the wrong conclusions(that's why I appreciate your and mackrackit's help so much)

    Speaking of help, I blew the dust of the old LCD and ran a modified program from mackrackits link:

    Code:
    MyVAR VAR BYTE
    Mybyte var byte
    Mybit VAR bit
    
    LET MyByte = 7
    
    For MyVar = 0 to 7
    MyBit = MyByte.0(MyVar)
    LCDOut $FE,1,"Bit ",#MyVar,"=",#MyBit
    Pause 2000
    Next MyVar
    When I ran it, Bits 0-1-2 were 1's the rest 0's following the pattern for Bin 7. So onto Bruce's code below:

    Code:
    ' Only DAT_OUT bits 1 and 2 are used. We add a few 1's in bit
        ' positions 0,3,5,7 to balance out the data packet being sent.
        DAT_OUT = %10101001
        ' Get data on button inputs & invert 0's to 1's
        DAT_OUT.0[1]=~GPIO.3
        DAT_OUT.0[2]=~GPIO.4
        INTCON.0 = 0  ' Clear int on change flag
          
        ' Build checksum of 2 data bytes
        CHK_SUM = (DAT_OUT * 2)
    Well the checksum would be two BYTES of:
    Code:
    DAT_OUT = %10101001
    With bits 1 & 2 being 0's (not inverted).....I think.


    Code:
    DAT_OUT = %10101001  DAT_OUT.0[1]=~GPIO.3 DAT_OUT.0[2]=~GPIO.4
    Would mean (I think again) bit 1 & 2 would invert to a 1 in the DAT_OUT_BYTE. Or saying that maybe it's only bits 1 & 2 that are inverted and sent. Mm, not sure but I'll go with the first option.

    Tin hat on, duck, am I close? (if not, just say so and I'll carry on thinking / reading).

    Dave
    Last edited by LEDave; - 15th November 2010 at 21:44.

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