12f675_fuse_about_to_blow!

[LEDave]

I've just spent two hours working on a post which I'm not going to post for the minute.

However Question:

How does:

DAT_OUT.0[1]

work? Or were do I look for the solution, is it in the manual? (I'd rather try and find the answer) if I can't I'll ask

The whole piece of code is:

DAT_OUT.0[1]=~GPIO.3

I think the

~GPIO.3

part simply sends to GPIO.3

From the manual:

If you don't want MicroCode Studio to interpret a control sequence, but rather send it as normal characters, then just use the tilda symbol (~) in front of the $ or # symbol. For example, letter ~#9712345 would be sent as letter #9712345.

Have I got that bit right?

Dave

[mackrackit]

(I'd rather try and find the answer) if I can't I'll ask

COOL!!!

"~" Look at the table under Math Operators 4.17 in the PBP manual.

And these may help.
http://www.picbasic.co.uk/forum/showthread.php?t=544
http://www.picbasic.co.uk/forum/show...1955#post91955
http://www.picbasic.co.uk/forum/show...&p=189#post189

You may want to set up a little test program and send values to a LCD or something to play with this.

[LEDave]

You may want to set up a little test program and send values to a LCD or something to play with this.

I will, the LCD's been looking a little lonely lately. I'll let you know how I get on.

Cheers mackrackit, you're a star.

[LEDave]

~ Bitwise NOT

So it's a Bitwise NOT then (well I've never heard of that one before, I'll get straight on it)

And not:

If you don't want MicroCode Studio to interpret a control sequence, but rather send it as normal characters, then just use the tilda symbol (~) in front of the $ or # symbol. For example, letter ~#9712345 would be sent as letter #9712345.

Like I thought it was. I can be almost dangerous with my assumptions sometimes

Dave

[HenrikOlsson]

Hi Dave,
I'm jumping in here.... The docs you've quoted is the docs for MicroCodeStudio, specifically its built in terminal emulator where the ~ means what you've quoted.

But in the PBP language ~ means bitwise NOT, negate or invert - whatever you like.

GPIO.0 = ~GPIO.1       'Set GPIO.0 to the inverted state of GPIO.1

/Henrik.

[LEDave]

Hi Henrik,

Yes, NOT GATE or inverted output, here's a Wiki link for any other newbies:

http://en.wikipedia.org/wiki/Inverter_(logic_gate)

Like I said in my post above, it's easy to jump to the wrong conclusions(that's why I appreciate your and mackrackit's help so much)

Speaking of help, I blew the dust of the old LCD and ran a modified program from mackrackits link:

MyVAR VAR BYTE
Mybyte var byte
Mybit VAR bit

LET MyByte = 7

For MyVar = 0 to 7
MyBit = MyByte.0(MyVar)
LCDOut $FE,1,"Bit ",#MyVar,"=",#MyBit
Pause 2000
Next MyVar

When I ran it, Bits 0-1-2 were 1's the rest 0's following the pattern for Bin 7. So onto Bruce's code below:

' Only DAT_OUT bits 1 and 2 are used. We add a few 1's in bit
    ' positions 0,3,5,7 to balance out the data packet being sent.
    DAT_OUT = %10101001
    ' Get data on button inputs & invert 0's to 1's
    DAT_OUT.0[1]=~GPIO.3
    DAT_OUT.0[2]=~GPIO.4
    INTCON.0 = 0  ' Clear int on change flag
      
    ' Build checksum of 2 data bytes
    CHK_SUM = (DAT_OUT * 2)

Well the checksum would be two BYTES of:

DAT_OUT = %10101001

With bits 1 & 2 being 0's (not inverted).....I think.

DAT_OUT = %10101001  DAT_OUT.0[1]=~GPIO.3 DAT_OUT.0[2]=~GPIO.4

Would mean (I think again) bit 1 & 2 would invert to a 1 in the DAT_OUT_BYTE. Or saying that maybe it's only bits 1 & 2 that are inverted and sent. Mm, not sure but I'll go with the first option.

Tin hat on, duck, am I close? (if not, just say so and I'll carry on thinking / reading).

Dave

[mackrackit]

Tin hat on

I wear one made of aluminum foil...

IF (GPIO.3=1) AND (GPIO.4=1) THEN

Because of this both bits in question are "1" when not pressed. So they will invert to "0".
If the thing was not sleeping that is.

But wait...

DAT_OUT = %10101001

They are "0"...

What if one of the buttons are pressed?

In the end, all eight bits of DAT_OUT are sent.

Yes, I am being a cryptic smart _ _ _.