How to decode an SMS which looks like this ...

[aratti]

How can I modify the above syntax to start loading from 9 to 19 & NOT 0 to 12?

Use two arrays, one for serin2 and one for serout

For A0=0 to 11
SecondArray[A0+9]=FirstArray[A0]
next A0

Al.

[financecatalyst]

Hi Aratti
Here is a snapshot of what I have done till now:

num var byte[12]
sum var byte[21]
baud con 188

sum[0] = "A"
sum[1] = "T"
sum[2] = "+"
sum[3] = "C"
sum[4] = "M"
sum[5] = "G"
sum[6] = "S"
sum[7] = "="
sum[21]= 13

Serin2 rx,baud,5000,main,[WAIT("REC UNREAD"),SKIP 3, STR num\12, skip 28, STR sms\8]
checkms:
If sms[0]="d" and sms[1]="e" and sms[2]="a" and sms[3]="c" and sms[4]="t" then
For c=0 to 12
sum[c+8]=num[c]
next c
For c=0 to 21
serout tx,T2400,[sum[c]]
next c
Serin2 rx,baud,5000,checkms,[WAIT(">")]


This arrangement is not working. Can you advise me of whats wrong. Many thanks for your time in advance

[aratti]

In your code you use the byte variable "C" but I don't see it declared.

Did you include "MODEDEFS.BAS" in your code?

num var byte[12]

For c=0 to 12 ' you will need 13 bytes here
sum[c+8]=num[c]
next c

How long is your phone number? You have declared an array (num) of 12 bytes but the for/next loop is trying to use 13 bytes!

Also the array sum is declared for 21 and you are attempting to use 22 (you have sum[21]= 13) This is an array of 22 bytes!
Remember that you have to count also the zero.

So adjust both the arrays as per the lenght of your phone number ( if 13 digits then you need 13 in the declaration and 13 in the string numerical. If on the contrary the phone lenght is 12 digits then modify the for/next loop to For c=0 to 11 and put byte array sum var byte[22]


Al.

[financecatalyst]

Hi
My number length is +447832225144 (0-12)(or 13 if counted from 1)

I declared variable num var byte[12] because it can take my number from num[0]="+" to num[12]="4"

I also declared sum var byte[21] because :
sum[0]="A" and so on upto sum[7]="="
and further
sum[8]="+"
sum[9]="4"
sum[10]="4"
sum[11]="7"
sum[12]="8"
sum[13]="3"
sum[14]="2"
sum[15]="2"
sum[16]="2"
sum[17]="5"
sum[18]="1"
sum[19]="4"
sum[20]="4"
sum[21]=13

and to fill sum[8] to sum[20] we need loop 13 times (sum[8] included), and so c=0 to 12

Also while serout it needs to transmit whole sum[0] to sum[21] so c=0 to 21.

Do you still feel this is the wrong way? Thanks

[aratti]

Include "MODEDEFS.BAS"
num var byte[13]
sum var byte[22]
c var byte

baud con 188

sum[0] = "A"
sum[1] = "T"
sum[2] = "+"
sum[3] = "C"
sum[4] = "M"
sum[5] = "G"
sum[6] = "S"
sum[7] = "="
sum[21]= 13

Serin2 rx,baud,5000,main,[WAIT("REC UNREAD"),SKIP 3, STR num\13, skip 28, STR sms\8]
checkms:
If sms[0]="d" and sms[1]="e" and sms[2]="a" and sms[3]="c" and sms[4]="t" then
For c=0 to 12
sum[c+8]=num[c]
next c
For c=0 to 21
serout tx,T2400,[sum[c]]
next c
Serin2 rx,baud,5000,checkms,[WAIT(">")]

The above (marked in red) are the correction needed.

Al.

[financecatalyst]

I have used a special routine so that to know if code is not getting stuck atleast after 5 tries which is as follows:

If sms[0]="d" and sms[1]="e" and sms[2]="a" and sms[3]="c" and sms[4]="t" then
i=i+1
if i=5 then
while 1
toggle portb.6
pause 100
wend : endif

for c=0 to 12
sum[c+8]=num[c]
next c
for c=0 to 21
serout tx,T2400,[sum[c]]
next c

Serin2 rx,baud,5000,checkms,[WAIT(">")]

Problem is that since I have made the last change of serin2....STR num\13, the code is getting stuck somewhere and not moving at all as it is not entering the toggle loop which it should after waiting 5 times for ">".

[aratti]

Sorry, I have forgotten to cange also the skip value after the string numeral:

Serin2 rx,baud,5000,main,[WAIT("REC UNREAD"),SKIP 3, STR num\13, skip 27, STR sms\8]

This should be one less since you have increased one byte the string.

Al.