How to decode an SMS which looks like this ...

[financecatalyst]

Use this code:

serout2 tx,baud,["AT+CMGS=",STR num\12,13]

Where:


num[0]="+"
num[1]="4"
num[2]="4"
....................

Al.

I tried the above way but sorry its not working like this.

[aratti]

I tried the above way but sorry its not working like this.

You can tray with SEROUT which seems working better.

Num     var Byte [21]
A0        var Byte

Num[0] = "A"
Num[1] = "T"
Num[2] = "+"
Num[3] = "C"
Num[4] = "M"
Num[5] = "G"
Num[6] = "S"
Num[7] = "="
Num[8] = "+"
Num[20]= 13 ' Last array variable MUST be 13

' The above are the constant value

'From Num[9] to Num[19] load your number
Num[9[] = "4"
Num[10] = "4"
Num[11] = ?? ' etc. etc.


' dial and send the sms using the for next loop
For A0 = 0 to 20                         
serout Tx,T9600,[Num[A0]]   ' Change baud rate as per your need.
Next A0

Al.

[financecatalyst]

Thanks for the input, but to try this can you advise me how to load my number from num[9] to num[19] as I am only aware of loading the number using the following command which starts loading it from num[0] to num[12]:

Serin2 rx,baud,5000,main,[WAIT("REC UNREAD"),SKIP 3, STR num\12, skip 28, STR sms\8]

How can I modify the above syntax to start loading from 9 to 19 & NOT 0 to 12?

Thanks

[aratti]

How can I modify the above syntax to start loading from 9 to 19 & NOT 0 to 12?

Use two arrays, one for serin2 and one for serout

For A0=0 to 11
SecondArray[A0+9]=FirstArray[A0]
next A0

Al.

[financecatalyst]

Hi Aratti
Here is a snapshot of what I have done till now:

num var byte[12]
sum var byte[21]
baud con 188

sum[0] = "A"
sum[1] = "T"
sum[2] = "+"
sum[3] = "C"
sum[4] = "M"
sum[5] = "G"
sum[6] = "S"
sum[7] = "="
sum[21]= 13

Serin2 rx,baud,5000,main,[WAIT("REC UNREAD"),SKIP 3, STR num\12, skip 28, STR sms\8]
checkms:
If sms[0]="d" and sms[1]="e" and sms[2]="a" and sms[3]="c" and sms[4]="t" then
For c=0 to 12
sum[c+8]=num[c]
next c
For c=0 to 21
serout tx,T2400,[sum[c]]
next c
Serin2 rx,baud,5000,checkms,[WAIT(">")]


This arrangement is not working. Can you advise me of whats wrong. Many thanks for your time in advance

[aratti]

In your code you use the byte variable "C" but I don't see it declared.

Did you include "MODEDEFS.BAS" in your code?

num var byte[12]

For c=0 to 12 ' you will need 13 bytes here
sum[c+8]=num[c]
next c

How long is your phone number? You have declared an array (num) of 12 bytes but the for/next loop is trying to use 13 bytes!

Also the array sum is declared for 21 and you are attempting to use 22 (you have sum[21]= 13) This is an array of 22 bytes!
Remember that you have to count also the zero.

So adjust both the arrays as per the lenght of your phone number ( if 13 digits then you need 13 in the declaration and 13 in the string numerical. If on the contrary the phone lenght is 12 digits then modify the for/next loop to For c=0 to 11 and put byte array sum var byte[22]


Al.

[financecatalyst]

Hi
My number length is +447832225144 (0-12)(or 13 if counted from 1)

I declared variable num var byte[12] because it can take my number from num[0]="+" to num[12]="4"

I also declared sum var byte[21] because :
sum[0]="A" and so on upto sum[7]="="
and further
sum[8]="+"
sum[9]="4"
sum[10]="4"
sum[11]="7"
sum[12]="8"
sum[13]="3"
sum[14]="2"
sum[15]="2"
sum[16]="2"
sum[17]="5"
sum[18]="1"
sum[19]="4"
sum[20]="4"
sum[21]=13

and to fill sum[8] to sum[20] we need loop 13 times (sum[8] included), and so c=0 to 12

Also while serout it needs to transmit whole sum[0] to sum[21] so c=0 to 21.

Do you still feel this is the wrong way? Thanks