No dumb questions
Some of the confusion might go back to folks calling the resistor a current limiting device. It is and is not...
In this case look at it as a voltage limiter. But being volts and amps kinda go together...
Look at the math Ioannis gave you.
6. Calculate the resistor to be in series as (353 - 332.5)/.03 = 680 Ohms1. Have a 4x1N4004 or 4007 diodes as a rectifier, or even better a bridge rectifier (4 pins) for 500Volts/2-5Amps.
2. On the AC line, fuse and a small resistor for the in-rush currents, say 2-5 ohms.
3. After rectification a capacitor of 220uF/500 Volts.
4. Calculate maximum voltage as 250 Vac x 1,41=353 Volts DC on te capacitor.
5. Calculate the total drop of LEDs say 332.5 Volts. Calculate the number of LEDs 332.5/3,5= 95 LEDs.
6. Calculate the resistor to be in series as (353 - 332.5)/.03 = 680 Ohms
7. Calculate the power of the resistor .03 x .03 x 680= 620mW. I would go x4 to set it at 2,5Watts
Change .03 to .05 and the result is 410~ Ohms.
So lets say you are running 5 LEDs from 12 volts and each LED uses 3.5 volts and you want to run at 0.03 amps.
Well guess what... 5 LEDs at that voltage adds up to 17.5 volts.
4 LEDs? = 14 volts...
Do not need to worry here. Could be a bit dim...
3 LEDs? = 10.5 volts. Yup, now we have a problem. There is 1.5 volts to much.
12 - 10.5 = 1.5
1.5 / 0.03 = 50 Ohm resistor.
1.5 / 0.05 = 30 Ohm resistor.
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