Programming Problem PIC12F683

[StoneColdFuzzy]

I'm trying to understand how the below statement makes GP3 an input. I understand that a 1 will make it an input, but how does that 1 digit relate to GP3? Perhaps this is an error and it actually makes GP4 an input?

Copied from elsewhere on this forum:

TRISIO = %00010000 'GP3 as input

~ Dave

[mister_e]

GPIO.3 is an input only, it just can't be configured as an output. Check your datasheet under TRISIO register, you'll discover that BIT3 is a read only bit... so whatever value you put there... it will always be set as an input.

[StoneColdFuzzy]

GPIO.3 is an input only, it just can't be configured as an output. Check your datasheet under TRISIO register, you'll discover that BIT3 is a read only bit... so whatever value you put there... it will always be set as an input.

I understand that. What I don't understand is how the digits in the positions that they are in relate to their respective pins.

~ Dave

[mister_e]

i'm not sure to follow you then... let's see if the following lines could give you some lights

'GPIO Bits 76543210
TRISIO  = %00001010
        '  xx------- Not implemented, don't care
        '  --0------ GP5 = output
        '  ---0----- GP4 = Output
        '  ----1---- GP3 = Input, Read only bit, input only, regardless to what you write here       
        '  -----0--- GP2 = Output
        '  ------1-- GP1 = input
        '  -------0- GP0 = Output

[StoneColdFuzzy]

OK, now I get it; I have to look at the table in the data sheet. I had copied that code from the following string:

http://www.picbasic.co.uk/forum/show...ight=pic12f683

So, I was correct that TRISIO = %00010000 makes GP4 an input.

~ Dave

[mister_e]

Yup GP4 AND GP3

[StoneColdFuzzy]

Thank you very much!

~ Dave