Thanks Darrel for your formulae. Substituting 1023 for the 5 I get
1023/1023*256 *10=2560(Quanta). I was using 2600,now from Pic this gives true 10bit number(1023) at full scale that is sent to pc to be scaled,damped,averaged etc.
Tom
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Thanks Darrel for your formulae. Substituting 1023 for the 5 I get
1023/1023*256 *10=2560(Quanta). I was using 2600,now from Pic this gives true 10bit number(1023) at full scale that is sent to pc to be scaled,damped,averaged etc.
Tom
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