power problem (newbie here!)


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  1. #1
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    Sep 2004
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    Smile

    Hi Mister E,

    Thanks for stepping in there. I kinda got off track with his original question!

    BobK

  2. #2
    Join Date
    Apr 2009
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    Default thanks! problem solved!

    Thank you gentlemen,

    what I had (crucially!) forgotten to add, was that the program on the pic would stop working entirely when the more than two segments were on at a time. I have since found that it must be due to the PIC's current sourcing limitations (is this correct?). Regardless, I have added some CD4050BE buffers and now it all works fine.

    I really appreciate your time and expertise. thank you.

    Ps Not using a LCD as I don't have one! Beside, there's something appealing, almost 'retro' about 7 segment displays I find....

    Code:
     
    test code tags
    Last edited by clocks; - 1st May 2009 at 01:31.

  3. #3
    Join Date
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    Angry Hot topic ?

    Hi Steve + Clocks

    You do not use 105, but 4 x 105 mA ... ( no multiplexing !!! )

    so, at least 2v * 420 mA = 850 mW to dissipate in the 7805 !!!

    some cooling necessary then !!! ( 10° C/W will be Ok )

    Alain
    ************************************************** ***********************
    Why insist on using 32 Bits when you're not even able to deal with the first 8 ones ??? ehhhhhh ...
    ************************************************** ***********************
    IF there is the word "Problem" in your question ...
    certainly the answer is " RTFM " or " RTFDataSheet " !!!
    *****************************************

  4. #4
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    Default cooling

    Hi Alain,

    Indeed - no multiplexing (I need bright displays).

    How do cool this down - or are there high rated voltage regulators out there?
    I don't understand your last sentence; what is : 10° C/W?

    thanks for your help!

  5. #5
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    Lightbulb

    Quote Originally Posted by clocks View Post

    I don't understand your last sentence; what is : 10° C/W?
    Hi,

    It's the thermal resistance of the dissipator to use ... it's like Resistance's "Ohms" ... but for heat dissipation value.

    That means it will heat at a rate of 10°C per dissipated Watt ... in your design, the temp of dissipator will be ( at blind sight ! ) ~ 25°C + (2 x 10°C) = 45°C

    Alain
    ************************************************** ***********************
    Why insist on using 32 Bits when you're not even able to deal with the first 8 ones ??? ehhhhhh ...
    ************************************************** ***********************
    IF there is the word "Problem" in your question ...
    certainly the answer is " RTFM " or " RTFDataSheet " !!!
    *****************************************

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