Howdy

I have not tried this yet, but am confused on the definition of "REV" on page 39 of the PBP Compiler manual, section 4.17.11

" REV reverses the order of the lowest bits in a value. The number of bits to be reversed is from 1 to 32. "

The example shows:

B0 = %10101100 REV 4 'sets B0 to %00000011

I thought only the lowest 4 bits would be reversed - why are bits 5 and 7 also changed? (set to 0) ?

I Suppose I could just write a short program and try it . . . . .

Ken