decrypted data


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Thread: decrypted data

  1. #1
    Join Date
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    Default decrypted data

    Je cherche a decrypted data and apparently no one understands the method of encryption.
    I think what is encrypted but I can not find how, and you
    how you have done to conceal or render unreadable data in a small eeprom?

    http://www.asmfr.com/forum/sujet-ASM...E_1267692.aspx

    To clear the text:
    1212131323323434 = 45454556567878989890
    VUQR5O UKEL7Y N7MF69 OANL17 NNMOIK RFJMW8 4PUO2V EXAXGE RNNNL2 ZQLIXZ
    NKXZLI XJMZZJ JKFNIZ DHT5DR H0FLRD ZPH4DZ VR3XDT JDXVPL DJJDHP LDLJDX
    VRFQTH 6BZTNB HTDVJB VVBBVZ LNVPDL V2XBTX HZT4XB TNDR2F BTJDRF JJZXPX
    X29JJX Z23XJZ T83QRJ ZZVJFD VTFFH

  2. #2
    Join Date
    May 2004
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    NW France
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    3,648


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    Angry

    Hi, "KAD" ou whatever your pseudo ...

    No use to SPAM every PIC Forum on the NET ...

    add to that asm

    ( which Pics used ??? ... I'd really like to know )

    Code:
    00405853   . 50             PUSH EAX 
    00405854   . 52             PUSH EDX 
    00405855   . 8BD1           MOV EDX,ECX 
    00405857   . E8 ABFFFFFF    CALL VIEW1.00405807 
    0040585C   . 5A             POP EDX 
    0040585D   . 58             POP EAX

    is not exactly the main language here ...

    Encore un génie qui restera méconnu ...

    Alain
    Last edited by Acetronics2; - 11th February 2009 at 14:15.
    ************************************************** ***********************
    Why insist on using 32 Bits when you're not even able to deal with the first 8 ones ??? ehhhhhh ...
    ************************************************** ***********************
    IF there is the word "Problem" in your question ...
    certainly the answer is " RTFM " or " RTFDataSheet " !!!
    *****************************************

  3. #3
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    Default cryptage

    Hi

    This is a pic 16F876, the party is on the site is the program reception
    as hyperterminal.


    Esque table that will use the program to encrypt or decrypt is
    used to rebuild his method?

    It decryption routine that I can not locate, because the encryption is done
    in an electronic circuit that sends data to your PC.

    Maybe xor encryption or modifications ascii characters to scramble
    the text?

    a good knowledge of ASM and can surely find the solution and decrypt
    it easily, it's hard for beginners.

    I hope to find help on this forum

    merci
    A+

  4. #4
    Join Date
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    Default What are you looking for?

    Are you looking for:

    A: A way to encrypt and decrypt your own data using PBP. If this is what you are looking for there are several ways to do it. TEA, XTEA and so on.. or a more simple XOR encryption

    B: Get help to decrypt information from a different source than your own?


    ??

  5. #5
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    Default eeprom

    Hello

    I think it's complicated, but you must know.
    And you how you could have done to protect data of a eeprom 24lc512
    Or perhaps the program that sends false with true and blurs the text.
    thank you for your help

  6. #6
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    Default Decrypte

    helo


    Apparently in order to decode it must test all the values from 0 to 255 and
    My case I'm only 10 digits? 0 to 9. As is always numeric characters
    over a length of 40 characters, there will be several repetitions of figure?

    If coding for each digit is a different value to not be able to compare
    compared to its own value and its relative position in the text encrypt
    so it will not have duplicates so it must be visible in the text by encrypting
    report its presence (1 time only) or all the characters this one
    both in the text after eliminating pressent characters several times, remains in the form code.

    adqtuy / egil / pjkn / obfxzh
    (1 time) / (2 times) / (3 times) / (4 5 8 9 times)

    (A d t q u y) once in the text

    9 9 9 9 8 8 8 8 7777 6666 = 5555 4444 3333 2222 1111
    adqtuy - - - - - - - - - - -----------------------------------

    Example: 1234567890123456 = 78900987654321987654
    or 1111111111111111 = 11111111111111111111
    or 1111777511456421 = 66880044411009922336


    and the first digit has a different value of the second and so on. .... So the first 1 will be A, B will be 1 second and so on, more characters to scramble.

    So with 10 digits and can not exceed 255 reduces its encryption.

    Converted to decimal 0 = 48 and 30 in Hexa
    255: 30 = 9 MAX 255: 48 MAX = 6

    9 converted to decimal = 57 and 39 in Hexa
    255: 39 = 7 MAX 255: 57 = 65 MAXI

    So the division, subtraction, multiplication will not be used and still adding
    that may serve, by inference we can easily find its encryption method.

    Permuting rest but will have identical characters and easily detectable.
    or the formula in exel and must be tested from 0 to 255.

    EXEL SOUX = ((0 * C86/256)-T (0 * C86/256)) * 256

    EXEL SOUX = ((255 * C86/256)-ENT (255 * C86/256)) * 256



    Which are coded and which are repeated, have tested the formula in exel there are chances of
    Find a match and that number is found the rest will be easy.

    I clear the text and I encrypt the text, and my friend only encryption key but
    do not know the plaintext

    Its key it can decrypt and discover the plaintext, I guess it is not
    also complicated, because the figures have the same value once encrypt

    Example: A value will b 5, an R-value will be 0 ... etc ...

    So they will not take the value of another figure, and will not be repeated
    in the encrypt text, it will always be one (b for 5) and no other (b)?
    significantly reduced its combinations.







    On the forums:

    Simply because this key will affect the interference characters by their ASCII value.

    ASCII codes represent the letters A to Z (eg "A" is 65, "B" is 66, ...) and all the figures and the other symbols on your keyboard.

    But the problem is that ASCII values range from 0 to 255.

    The most important part of encryption is the way to blur the text.
    ASCII does not constitute an encoding of secret is to encrypt the ASCII code
    Encryption using the following:
    C note on the encryption feature which, at any integer n in [0, 255] combines the remainder of the division by 256 of 7n. Let C (n) the rest. We use the formula "= MOD (7 * n, 256).
    Attached Files Attached Files
    Last edited by RAYMON; - 14th February 2009 at 10:34.

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