Problems with ADC

[mcbeasleyjr]

        PORTB = (LIGHT >>2)
        PORTD.6 = LIGHT.0
        PORTD.7 = LIGHT.1

Doesn't this line just shift everything two bits to the right:

portb = (light >>2)

By doing this I'm actually losing two bits right?

[mister_e]

LIGHT is a Word, PORT is a BYTE... this is always hard to fit 16bits in a 8 bit register huh?

LIGHT>>2 - yes it shift two position to the right... yes you miss bit0 and bit1, but the next lines
PORTD.6 = LIGHT.0
PORTD.7 = LIGHT.1

place them on PORTD.

no lost at all.

None of your bit are lost LIGHT>>2 as long as you dont use something like
LIGHT=LIGHT>>2

[mcbeasleyjr]

ok i was thinking that bit 0 and bit 1 would just be moved to where bits 2 and bits 3 are... thus showing bits 0 and 1 twice and losing bits 8 and 9 with the code you provided me with... i'll give it a shot and see what happens...