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That is a simple voltage divider. 5v supply /5k ohm = .001 Amp
5v / 10k ohm = .0005 amp how much current do you want to waste ?
Assuming zero current flow into the PIC (impossible I know) the voltage will be linear across either one. It gets less true as the PIC begins to load the voltage divider, and as this parasitic loss increases the more suitable the lower resistance becomes.
If you do not believe in MAGIC, Consider how currency has value simply by printing it, and is then traded for real assets.
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Gold is the money of kings, silver is the money of gentlemen, barter is the money of peasants - but debt is the money of slaves
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There simply is no "Happy Spam" If you do it you will disappear from this forum.
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