Floating point math

[LinkMTech]

This works fine, and I get a value that varys between 11 and 90. (When just outputting it to an LCD)

BUT, now I want to know what the real value is, not this representation of the actual voltage.

Assuming an ADCIN of 10bits:
The displayed value comes from Vdd/10bit or 5V/1024= 4.88mv per bit. So 11* 4.88mv= 53.7mv and 90*4.88mv= 439.5mV. I would measure with a DMM to confirm or use a known good voltage at say 2.5V to see a reading of 512 on your display.
Knowing this, you might be able to multiply the ADCIN value to another for your desired display.

[Glenn]

Assuming an ADCIN of 10bits:
The displayed value comes from Vdd/10bit or 5V/1024= 4.88mv per bit. So 11* 4.88mv= 53.7mv and 90*4.88mv= 439.5mV

Aaah.. ofcourse, stupid me, if I had stopped looking for answears in the manual and instead been thinking of how a DA-converter works this would have been obvious.

Still, how do I handle decimals ? ..if I just want to display the voltage on the LCD to begin with ? ..and then cobnvert it to a real value with the formula ?

[LinkMTech]

I usually take my decimal numbers and multiply them up to make it an integer. Take this simple equation as an example:
15 * 3/5 = 9
Since 3/5=.6
I mulitiply .6 by 10 to get 6. And divide the whole thing by 10 afterwards.
(15*6)/10=9
I know this is kinda simple but with calculator in hand along with trial and error to check my math (I'm a little weak) I eventually get there.

[LinkMTech]

Forget that lame suggestion, here's a better one from the experts:

http://www.picbasic.co.uk/forum/showthread.php?t=712