Count Bits, Choose High or Low?

[sayzer]

IF DT's routine is too complicated for you, which usually is for me, then take a look at this one.
This should be faster then yours I guess.

<font color="#000000">ErrorCheck:
    HighCount = <font color="#FF0000">0
    </font>LowCount  = <font color="#FF0000">8
    </font>i         = <font color="#FF0000">0

    </font><font color="#000080"><b>WHILE </b></font>i &lt; <font color="#FF0000">8
          </font>n = testByte.<font color="#FF0000">0</font>[i]          <font color="#000080"><i>'Read bit.
          </i></font>LowCount  = LowCount - n   <font color="#000080"><i>'sub. bits.
          </i></font>HighCount = HighCount + n  <font color="#000080"><i>'add bits.
          </i></font>i = i + <font color="#FF0000">1                  </font><font color="#000080"><i>'incr. bit.
    </i><b>WEND


    </b></font>testByte = <font color="#FF0000">$00                    </font><font color="#000080"><i>'Assign value.
    </i><b>IF </b></font>HighCount &gt;= LowCount <font color="#000080"><b>THEN </b></font>testByte = <font color="#FF0000">$FF  </font><font color="#000080"><i>'change value if true.
         
</i><b>RETURN
</b></font>

Edit: I did not understand the logic behind this statement:
"This will eliminate any bit errors as long as it's not more than 3 bit errors per byte."
You may cut the loop off if this is true and reduce the time into half of what it takes.

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