Lower 4 Bits?

[Bruce]

This should not return any errors.

SecOnes var byte
Seconds var byte
SecOnes = Seconds & $0f

Of course the result will be unknown since none of the variables are initialized, but it
definitely should not return an error.

Why does it say $0f ???

Because a value of $0F (%00001111) ANDed with another 8-bit value will return all
0's in the upper 4-bits of the result MASKing the upper 4-bits out.

[jderson]

Thank you, Bruce for the explanation. I now understand how it works. I failed to explain that I'm trying to "add-on" (within the Main portion of my program) to DT's Elapsed_INT-18. That's why I said the Seconds variable was already declared. So, when I declare it again, I get the redefinition error. I'll try adding the SecOnes stuff to HIS program!