Bit variables... typo?

This snippet below is taken from MElabs website:
http://www.melabs.com/resources/articles/pinaccess.htm

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Specifying bits with variables

Sometimes it is desirable to specify the bit with a variable in your program. This allows you to write to different bits, based on some condition in your code.

Let's write a code snippet which will count 0 to 7 and make the corresponding bit on PORTB high for each count. To do this, we will use a bit offset.
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Code:

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i    var    byte    ' i will hold our count
TRISB = %00000000    'set all PORTB pins as output

For i = 0 To 7    'loop for 8 counts

    PORTB = %00000000    'make all pins low

    PORTB.0[i] = 1        'make pin number i high

    Pause 500            'pause for half a second

Next i        'go to the next count

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Notice the PORTB.0[i] line is that a typo?
If not why is the "[i]" located next to ".0"?
Please explain how it works

Thanks,
Tom

Quote:

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Notice the PORTB.0[i] line is that a typo?
If not why is the "[i]" located next to ".0"?
Please explain how it works

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one things is stupid frome MELABS, is not allowing to write...

PORTA.i

anyway, we can consider PORTB.0[i] as a kinda typo.

Too bad...I was hoping to use it in an array.

Anyway, so if we can't use an array here then what's the point of the example?

Thanks,
Tom

Depending of what you want to do with an array... what do you plan to do?

Nothing particular in this case. Just that the example said that you can specify the bit with a variable in your program which I didn't see in the manual. I thought that would be usefull sometimes. But I didn't understand the syntax.

Code:

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PORTB.0[i] = 1

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Going back to the example they probably meant this:

Code:

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PORTB.[i] = 1

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...so I guess you can use it in an array otherwise they wouldn't show it, right?

Anyway, I'm pretty new to the PBP and try to pick up new things when I see them. Also PBP is very limited compared to PC languages so every little trick helps.

Ok, i'm not sure what you know and what you don't so here's fulll explanation.

PORTB.0=1

high level state to PORTB bit 0 (RB0). This is doing the same thing as HIGH PORTB.0

PORTB.0[i]=1

high level state to PORTB bit specify by i variable

So let's say i=4, this will place PORTB bit 4 (RB4) to high level.

i don't see lots of appliance for this function since i always use specific name to access an PORT pin.

hope this put some lights

regards

It's all here if you search for it...

http://www.picbasic.co.uk/forum/show...=&threadid=544