hi,
i need a way to take 6V and drop it down to 5V in a 'clean' way, the output voltage of 5V
must stay pretty constant. I have a motor running off the 6V and a receiver (from a radio control) that needs a constant 5V
any help would be great, thx
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hi,
i need a way to take 6V and drop it down to 5V in a 'clean' way, the output voltage of 5V
must stay pretty constant. I have a motor running off the 6V and a receiver (from a radio control) that needs a constant 5V
any help would be great, thx
Do a search for LDO Voltage regulator. Plenty of them here and there.
Or put 1 or 2 diodes in series with the 6 volt, it drops immediatly!
Yes, but when the battery will drop of 0.1 volt, the diode output will also be 0.1V less.
It's true what you say !
Put a small choke in series with whatever power dropping device you have chosen to dampen some of the noise generated by the motor. . .a ferrite bead is useful too, best way is use different power source . . .Quote:
Originally Posted by Fisher
And a capacitor across the motor terminals.
I would think that any receiver could tolerate running from the same supply as your 'motor', with the above mentioned 'cleaning' of the power supply itself from the noise caused by the motor.Quote:
Originally Posted by Fisher
What I think would worry me would be the voltage droop caused by the motor starting up causing the overall voltage to drop too low to support safe operation of the receiver.
cuz the problem is that i have 2 cordless 18V drills running off of a 6V 42 amp per hour battery with a 12V 38 amp per hour battery. i also have 2 little 12V motors (draws less then an amp) hooked out to the 12V. The reciever needs a constant 5V , i could use a 7805 regulator with the 12V, but i would like to use the 6V for the reciever's 5V.
These are nice if you do not mind the extra parts.
http://webench.national.com/ss1/ss?V...1I=.5&op_TA=30
If you don't need much current, add a 1K resistor in series and a parallel zener diode.