Interrupt On both (Rising and Falling)
Hi to all.
In my project I've used external interrupt. Rising edge on RB0 causes to occure an Interrupt. In the ISR, data are read from serial EEPROM. I've used a micro switch for determining the direction of movement. For example rising edge (1 to 0) implies right direction and falling edge (0 to 1) left direction. I need both of edge change detection. It means that in right direction should be done one thing and in left direction another thing. Unfortunately I can only detect one of directions: right or left! (By setting of OPTION register). How can I determine direction of movement?
At the first I wanted to implement it by PORTB chane interrupt (RBIE). I defined all of pins of portB as output except for RB0. But it didn't work and it was so unstable.
Please help me.
Thanks alot
My car doesn't start - Why ???
Hi,Yasser
First , In the title , understand we do not know at all what you did ( hardware ) nor what you wrote ( software ) ... and there are no "crystal ball" option on this forum ...
For the car ... " did you insert the key ??? " is a first question to consider ...
...
There's a funny thing in this feature ... the "end of mismatch" condition.
I think there were ( numerous ) threads about that on this forum. ( a SEARCH will be useful ...)
... in a word, you have to READ PortB in your interrupt stubb to get it that interrupt working properly ( see examples given ...)
BUT, as always ... only knowing which processor and compiler ... leaves NUMEROUS non-working reasons ...
Alain
1 Attachment(s)
My car has unknown problem!!
Thanks alot dear Acetronics.
I wrote this simple program for testing portB change interrupt.
'************************************************* ****************
'* LCD Deifnes *
'************************************************* ****************
DEFINE LCD_DREG PORTD ' I/O port where LCD is connected
DEFINE LCD_DBIT 4
DEFINE LCD_RSREG PORTD
DEFINE LCD_RSBIT 2 ' Register select pin
DEFINE LCD_EREG PORTD
DEFINE LCD_EBIT 3 ' Enable pin
DEFINE LCD_BITS 4 ' 4-bit data bus
DEFINE LCD_LINES 2 ' LCD has 2 character lines
'************************************************* ****************
'* Interrupt Initialzing *
'************************************************* ****************
INTCON = %10001000 ' GIE and RBIE are set
OPTION_REG = %10000000
'************************************************* ****************
'* Initialzation *
'************************************************* ****************
TRISB = %00010000
PORTB = 0
ON INTERRUPT GOTO DIRECTION
'************************************************* ****************
'* Main Program *
'************************************************* ****************
MAIN:
lcdout $fe,1
lcdout "Main Routine"
pause 500
GOTO MAIN
END
'************************************************* ****************
'* Interrupt Service Routine *
'************************************************* ****************
DISABLE
DIRECTION:
lcdout $fe,1
lcdout "Interrupt !!!"
PAUSE 100
INTCON.0 = 0
RESUME
ENABLE
I compiled it and downloaded HEX file to PIC. I use PROTEUS 6 pro for simulating my program.(My Circuit Attached) When I pushed start debugging button on
proteus an unusual thing happened. I think that program should work in main loop so "Main Routine" should be written on LCD! But as soon as program starts
executing, the message "Interrupt !!!" is shown on LCD!! even if the push button isn't pressed. Why it does not work correct?!!
You wrote for me: "... in a word, you have to READ PortB in your interrupt stubb to get it that interrupt working properly ( see examples given ...)" What do you maen? Could you tell me about given examples?
** Although I use PIC16F877 in this simulator, I want to use PIC16F84 in my project. **
