How to round number using integer only

Hello all,
I'm stuck on that one. How do you round a number using integer only? for example if I have a variable like 4557 I would like the results to become 4560 because the last digit is higher than 5 on the other end if I have a variable like 4554 the last digit is less than 5 so the variable remains 4554.
The trick is how to isolate the last digit to make the comparison? Any idea?
Regards,
Yves

You can use the DIG comand!

Let assume your word variable that contains 4557 is named R_Value, then:

AA0 VAR BYTE

AA0 = R_Value DIG 0
If AA0 > 5 then
R_Value = R_Value + (10 - AA0)
ENDIF

.... and you will round as requested.

Cheers


Al.

Quote:

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Originally Posted by Yvesmazzon

Hello all,
if I have a variable like 4557 I would like the results to become 4560 because the last digit is higher than 5 on the other end if I have a variable like 4554 the last digit is less than 5 so the variable remains 4554.
Regards,
Yves

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var = var * 10
say calculation arrives at 45576
var = var +5
var = var / 10
answer 4558

Norm